The Doppler Effect Equation & Calculating Frequency Change

This article was written my Mike Bannon of Thermaxx Jackets.


The Doppler Effect

For a moment, close your eyes and pretend you are standing on a sidewalk and an ambulance is swiftly approaching your position. You listen as the ambulance draws near, and after it passes, the pitch, or frequency, of the siren seems to change.

In 1842 Christian Doppler hypothesized that sound frequencies change, relative to the observer, when emitted from a moving sound source. In 1845 Buys Ballot proved Doppler’s Hypothesis correct. As the ambulance approaches, the waves seem shorter and the frequency seems higher than when it moves away from you. When it’s moving away, the waves seem longer and the frequency seems lower. The Doppler Effect is illustrated in the cartoon above.

Calculating the Frequency Change

The formula for determining the frequency during this event is as follows:

Math Equation

ƒ = observed frequency

c = speed of sound

Vs = velocity of source (negative if it’s moving toward the observer)

ƒ0 = emitted frequency of source

Suppose you are standing on the corner of 5th Avenue and 34th Street waiting for the light to change so you can cross the street. An approaching southbound ambulance is heading your way traveling at 35 miles per hour. If we know that the frequency of the ambulance siren is 700 Hz, we can calculate the frequency of what you hear:

c, the speed of sound, is 340.29 m/s

Vs, the velocity of the source, is 35 mi/h, or 15.6464 m/s

ƒ0, the frequency of the ambulance siren, is 700 Hz


Math Equationbecomes
(note: Vs is negative since the source is moving towards the observer)

math equation

which reduces to:

ƒ ≈ 734 Hz

Once the ambulance passes, the frequency of the sound decreases, or sounds “lower”. The same calculation is performed to determine the observed frequency, except in this case Vs is positive:

Math Equation

ƒ ≈ 669 Hz

A similar change in sound frequency is observed if the observer is moving towards a stationary sound source. In this case the formula is:

Math equation

Where Vr is the velocity of the receiver, or observer. (note: this is negative if the observer is moving away from the source).

So, as an example, if you are driving your boat at 50 knots towards a buoy with a foghorn emitting a 400 Hz signal, the frequency of the sound you hear would be:

Math equation

Where is Vr is 50 knots, or 25.722 m/s

Math Equation

ƒ ≈ 430 Hz

We can also calculate the observed frequency if both the source sound and the observer are moving towards each other. In this case, the formula is:


Math Equation

Now pretend that you and your friends are sitting on top of a tour bus heading southbound on 7th Avenue at 30 miles per hour. That same ambulance is heading towards your bus at 28 miles per hour. We can now calculate the frequency of what you hear:

Vr, the velocity of the source, is 30 mi/h, or 13.4112 m/s
Vs, the velocity of the source, is 28 mi/h, or 12.51712 m/s

Math Equation

ƒ ≈ 755 Hz


Sound waves seem to compress or elongate with moving sound source. Moving forward causing the waves in front to seemingly compress and waves in back to seemingly elongate. The sound coming from an approaching ambulance siren will have a higher pitch than when it’s moving away from you. This happens to be a very practical by-product of sound physics. We need to be able to differentiate between an approaching ambulance and a retreating one so we can take the necessary precautions like pulling our vehicles over to the side of the road.

Learn about Thermaxx sound insulation, or contact us.


About Thermaxx Jackets

Thermaxx Jackets was founded over 25 years ago with a single purpose: to save energy when traditional stay-in-place insulation is not practical. Combining expertise in heat loss, wireless monitoring, insulation design, and several other disciplines, we’ve become the #1 provider of removable insulation jackets and covers.
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5 Responses to The Doppler Effect Equation & Calculating Frequency Change

  1. Samad Korai says:

    YOU ARE A GENIUS!!! What my teachers couldnt teach me in years, you did it in 10 mins.

    I salute you man.

  2. Brillas says:

    I have a question, please. Assume a free-space and ray-tracing model as Fig. 1, the transmitter is stationary, the receiver is moving a and its velocity is 75km/h, the signal frequency is 1GHz. Please what is the doppler shift?

  3. Jangdiya John Barde says:

    thanks for you brief and short lesson I am great full

  4. Stacey says:

    I have been trying to understand different moving observer and source scenarios for months to get ready for my MCAT. This is by far the easiest to understand and straightforward explanation I was fortunate enough to find. THANK YOU!!

  5. O.B.Server says:

    Beautiful … especially since I just heard a passing siren and wondered if the velocity of the siren (vehicle) may be found if we know (hear) the two frequencies (approaching and receding. So arrived here.

    Also, does this mean we can find the frequency (f0 above) by taking an average of the approaching and receding frequencies? (Sampled appropriately.)

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